Text.WordBreak Class
Provides utility methods for splitting strings on word breaks and determining whether a character index represents a word boundary, using the generic word breaking algorithm defined in the Unicode Text Segmentation guidelines (Unicode Standard Annex #29).
This algorithm provides a reasonable default for many languages. However, it does not cover language or context specific requirements, and it does not provide meaningful results at all for languages that don't use spaces between words, such as Chinese, Japanese, Thai, Lao, Khmer, and others. Server-based word breaking services usually provide significantly better results with better performance.
Item Index
Methods
- _classify static
- _isWordBoundary static
- getUniqueWords static
- getWords static
- isWordBoundary static
Methods
_classify
-
string
Returns a character classification map for the specified string.
Parameters:
-
string
StringString to classify.
Returns:
_isWordBoundary
-
map
-
index
Returns true
if there is a word boundary between the
specified character index and the next character index (or the end of the
string).
Note that there are always word breaks at the beginning and end of a
string, so _isWordBoundary('', 0)
and
_isWordBoundary('a', 0)
will both return true
.
Parameters:
Returns:
getUniqueWords
-
string
-
options
Returns an array containing only unique words from the specified string.
For example, the string 'foo bar baz foo'
would result in
the array ['foo', 'bar', 'baz']
.
Parameters:
Returns:
getWords
-
string
-
options
Splits the specified string into an array of individual words.
Parameters:
-
string
StringString to split.
-
options
Object(optional) Options object containing zero or more of the following properties:
- ignoreCase (Boolean)
-
If
true
, the string will be converted to lowercase before being split. Default isfalse
. - includePunctuation (Boolean)
-
If
true
, the returned array will include punctuation characters. Default isfalse
. - includeWhitespace (Boolean)
-
If
true
, the returned array will include whitespace characters. Default isfalse
.
Returns:
isWordBoundary
-
string
-
index
Returns true
if there is a word boundary between the
specified character index and the next character index (or the end of the
string).
Note that there are always word breaks at the beginning and end of a
string, so isWordBoundary('', 0)
and
isWordBoundary('a', 0)
will both return true
.